20140201 20140202 ... 20140228
Any thoughts on this command? Does it work on your machine? Can you do the same thing with only 14 characters?
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can be replaced with grep (saving one command):| grep "^ *[0-9]"
Some (or none) leading space, followed by numbers. "printf" is a shell builtin so it's already quick, but the alternative bash way is:[ ${#DD} = 1 ] && DD=0$DD
If DD has length 1, then prefix it with a zero. So my command looks like:YYYY=2014; MM=02; for DD in $(cal $MM $YYYY | grep "^ *[0-9]"); do [ ${#DD} = 1 ] && DD=0$DD; echo $YYYY$MM$DD; done